# Facebook Hacker Cup 2012 Qualification Round Billboards Problem Solved

|We are starting preparations for Hacker Cup 2013 really early. Our first step is to prepare billboards to advertise the contest. We have text for hundreds of billboards, but we need your help to design them.

The billboards are of different sizes, but are all rectangular. The billboard widths and heights are all integers. We will supply you with the size in inches and the text we want printed. We want you to tell us how large we can print the text, such that it fits on the billboard without splitting any words across lines. Since this is to attract hackers like yourself, we will use a monospace font, meaning that all characters are of the same width (e.g.. ‘l’ and ‘m’ take up the same horizontal space, as do space characters). The characters in our font are of equal width and height, and there will be no additional spacing between adjacent characters or adjacent rows.

Let’s say we want to print the text “Facebook Hacker Cup 2013″ on a 350×100″ billboard. If we use a font size of 33” per character, then we can print “Facebook” on the first line, “Hacker Cup” on the second and “2013” on the third. The widest of the three lines is “Hacker Cup”, which is 330″ wide. There are three lines, so the total height is 99″. We cannot go any larger.

### Input

The first line of the input file contains a single integer T: the number of test cases. T lines follow, each representing a single test case in the form “W H S”. W and H are the width and height in inches of the available space. S is the text to be written.

### Output

Output T lines, one for each test case. For each case, output “Case #t: s”, where t is the test case number (starting from 1) and s is the maximum font size, in inches per character, we can use. The size must be an integral number of inches. If the text does not fit when printed at a size of 1″, then output 0.

### Constraints

- 1 ≤ T ≤ 20
- 1 ≤ W, H ≤ 1000
- The text will contain only lower-case letters a-z, upper-case letters A-Z, digits 0-9 and the space character
- The text will not start or end with the space character, and will never contain two adjacent space characters
- The text in each case contains at most 1000 characters

[Java] Billboards – Pastebin.com

**Billboards**

Billboards had the second-most correct solutions in the qualification round, with 3210 correct submissions. The maximum size of the billboard was 1000×1000, so checking every possible font size is efficient enough. We start with the smallest possible font size, 1, and test each higher size until we find a font size that doesn’t fit the sign. For each font size, convert the dimensions of the billboard into rows and columns by taking the floor of the dimension divided by the font size. Then lay out the words from the first row to the last, putting as many words as possible onto each row.

Here’s a solution in Python:

import sys

cases = sys.stdin.readlines()

def solve(width, height, words):

for size in range(1, 1 + max(width, height)):

cols, rows = width // size, height // size

w = list(reversed(words))

r, c = 1, 0

while w:

c = len(w.pop())

if c > cols:

# word is too wide to fit on this line

return size – 1

while w and not (c + 1 + len(w[-1]) > cols):

c += 1 + len(w.pop())

if not w:

# We fit everything, check the next larger font size

continue

r += 1

if r > rows:

# Too tall

return size – 1

c = 0

for case in range(1, len(cases)):

data = cases[case].split()

w, h = int(data[0]), int(data[1])

words = data[2:]

print “Case #{}: {}”.format(case, solve(w, h, words))